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  1. 线性代数 (det)是什么意思?_百度知道

    A矩阵的 行列式 (determinant),用符号det (A)表示。 行列式在数学中,是由解 线性方程组 产生的一种算式其 定义域 为nxn的矩阵 A,取值为一个 标量,写作det (A)或 | A | 。行列式可以看做是有向面 …

  2. linear algebra - How do I prove that $\det A= \det A^T

    Divide the leading and the trailing expressions by n n, we obtain det(A) = det(AT) det (A) = det (A T). Since this is a universal identity, it also works over commutative rings of finite characteristics.

  3. 海运中DEM与DET分别代表什么?所谓的免堆与免用?所谓场内场外分 …

    Aug 6, 2024 · 海运中,DEM和DET是两种常见的费用术语。DEM代表滞期费(Demurrage Charges),当船舶在港口停留超过预定时间,未能及时卸货或装货,船东会向租船人收取这部分费 …

  4. linear algebra - Why is $\det⁡ (-A)= (-1)^n\det (A)$? - Mathematics ...

    Typically we define determinants by a series of rules from which $\det (\alpha A)=\alpha^n\det (A)$ follows almost immediately. Even defining determinants as the expression used in Andrea's answer …

  5. prove that $\det (ABC) = \det (A) \det (B) \det (C)$ [for any $n×n ...

    Feb 7, 2020 · I was thinking about trying to argue because the numbers of a given matrix multiply as scalars, the determinant is the product of them all and because the order of the multiplication of det …

  6. 海运中DEM与DET分别代表什么?所谓的免堆与免用箱分别从什么时候 …

    Apr 16, 2015 · DET(Detention Charge):拘留费 2.免堆期(FREE DETENTION),意思是免去集装箱在目的港码头的堆存费用,主要是发生在收货人不能迅速清关,或因为货量较大的情况下,需要在 …

  7. linear algebra - How to prove $\det \left (e^A\right) = e ...

    Sep 6, 2022 · Prove $$\\det \\left( e^A \\right) = e^{\\operatorname{tr}(A)}$$ for all matrices $A \\in \\mathbb{C}^{n \\times n}$.

  8. The determinant of adjugate matrix - Mathematics Stack Exchange

    All you need to use is that important property, and det(XY) = det X det Y det (X Y) = det X det Y, and the formula for det cX det c X when c c is a constant (and you need to know det I det I). Try it!

  9. Why $\det (A^ {-1}) = 1/\det (A)$? - Mathematics Stack Exchange

    Jul 12, 2016 · That actually makes sense to me now. Thank you for your assistance!

  10. linear algebra - How to show that $\det (AB) =\det (A) \det (B ...

    Aug 28, 2011 · Once you buy this interpretation of the determinant, $\det (AB)=\det (A)\det (B)$ follows immediately because the whole point of matrix multiplication is that $AB$ corresponds to the …